..aaSSppp!! Don't get enough current for my circuit. it is the SDD3000 pre only.
I built a charge pump dual supply +15v and -15v from 9v with LT1054.
Measured as open the positive supply is 15V the negative is -15V,
when I put the supply into the circuit the + 15V become +12V and -15V become -5V... i think it is short of current.
Any suggestion ?
This guy uses only one chip having 8 ping (in the middle of the rotary switch) but I ignore what it could be...
https://trabantland.wordpress.com/categ ... amp-clone/
Thanks in advance.
ChargePump from 9VDC to +15V -15V not enough current
- Dirk_Hendrik
- Old Solderhand
Information
An LT should easily do that.
You're not powereing stuf like LED(s) from that +/-15 volts as well aren't you?
You're not powereing stuf like LED(s) from that +/-15 volts as well aren't you?
- Mbas974
- Resistor Ronker
ehm... I'm ... shell I say that I'm a bit honored to get an answer from you ?!!
Dirk you are one of my GURU and I take this chance to say you a big THANKS for all what I've learned from you !!
this is the charge pump:
http://forum.musikding.de/cpg/displayim ... m=14&pos=4
Now back to my problem...
The led is there but take the 9V nothing connected with the charge pump.
You (obviously) are right !! A LT can do that.
I've SOLVED NOW usinng a diode to connecting ground of the circuit.
For some reason that I'm not able to explain grounding the circuit with normal wire with the power's ground
it's reduce the supply, putting a diode as connection (1N5819 in my case) there is no loss of voltage in supply .
LET ME WISH A WONDERFUL 2012 to all the members of this fantastic forum!!!!
Dirk you are one of my GURU and I take this chance to say you a big THANKS for all what I've learned from you !!
this is the charge pump:
http://forum.musikding.de/cpg/displayim ... m=14&pos=4
Now back to my problem...
The led is there but take the 9V nothing connected with the charge pump.
You (obviously) are right !! A LT can do that.
I've SOLVED NOW usinng a diode to connecting ground of the circuit.
For some reason that I'm not able to explain grounding the circuit with normal wire with the power's ground
it's reduce the supply, putting a diode as connection (1N5819 in my case) there is no loss of voltage in supply .
LET ME WISH A WONDERFUL 2012 to all the members of this fantastic forum!!!!