On power up, the 100n cap is discharged (cap voltage=0), so the first inverter output goes high, causing the 220n to charge up to +9V slowly through the 1M resistor. The high level on the first inverter output also causes the second inverter output to go low, which reinforces the low at the input of the first inverter due to the positive feedback provided by the 100k resistor. The LED is on and the "Output" is high.YuGi wrote: Can you explain how it work? Sorry I don't know yet this kind of electronics.
When you press the switch, the 9V of charge on the 220n cap is dumped onto the 100n cap, causing the voltage at the first inverter's input to go higher than 6V, which is enough to make it's output change state. This turns the LED off and the "Output" terminal goes low.
If you held the switch closed, nothing would happen because the charge on the 220n is only higher than the threshold for a fraction of a second. It quickly is dumped into the 100n and through the 100k resistor. This is also what prevents "switch bounce" to cause false triggering.